Heat of Reaction.

>>> rouse of Reaction Aim: To determine the catch attack of reaction of NaOH with HCl Apparatus\Materials: Polythene Cup, Thermometer, Measuring Cylinder, NaOH, HCl. Procedure: (1) 25cm of HCl was dictated in polythene cup, (2) HCl was left to stand for 5 proceeding and then the temperature was taken (3) Steps 1-2 was repeat with NaOH instead of HCl, (4) NaOH was added to HCl in polythene cup and stirred for 5minutes and the highest temperature the liquid rose to was recorded. Results: sign temperature of NaOH - 32? Initial temperature of HCl - 31? Final temperature of mixture - 38? Temperature wage hike for NaOH = 6? Temperature rise for HCl = 7? pile of mixture = 50cm Mass of resultant = 50g 1 cm of solution has a mass of 1g numeral of moles present in 25cm of NaOH = .0025moles Heat produced = 1365KJ Calculations: (1) Mass of 1cm of solution = 1g since the dumbness of the solution is 1g per cm, (2) Number of moles of NaOH = volume incmxconcentration in mole s per dm 1000 cm = (25 x .1)/1000 = .0025moles (3) Heat produced = MC?? of NaOH+ MC?? of HCl = .

025kg X 4200 X (38?- 32?) NaOH = 630J (NaOH) = 025kg X 4200 X (38?- 31?) HCl = 735J (HCl) = 630J (NaOH) + 735J (HCl) = 1365J Conclusion: An energy-releasing reaction takes place when NaOH is involved with HCl. The amount of heat produced when .0025 moles of NaOH is mixed which .0025 Moles of HCl is equal to 1365J and the amount of heat that get out be produced when 1mole of NaOH reacts with 1mole of HCL will be equal to ((1 moles\ .1mole) X 1356j), 546KJ superb lab. Well organized. keen conclusion. And excellent calculations!! Needs sources! If you want to get a skinny essay, order it on our website: OrderEssay.net

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